There is a solution rt?

Dark Mode

2,533 views

4 votes

Tower $A$ is $90 \ m$ tall and tower $B$ is $140 \ m$ tall. They are $100 \ m$ apart. A horizontal skywalk connects the floors at $70 \ m$ in both the towers. If a taut rope connects the top of tower $A$ to the bottom tower $B,$ at what distance (in meters) from tower $A$ will the rope intersect the skywalk$?$

6 votes

Best answer

Tower $A$ is $90 \ m$

Tower $B$ is $140 \ m$

$A$ and $B$ are $100 \ m$ apart

To find$: EF$ distance

By proportionality theorem for $\triangle \ AEF$ and $\triangle \ ACD $

$\dfrac{AE}{AC}=\dfrac{EF}{CD}$

$\implies\dfrac{20}{90}=\dfrac{EF}{100}$

$\implies EF=\dfrac{2}{9}\times 100=22.22 \ m$

So,the answer is $22.22 \ m$

0 votes