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Two dice are thrown simultaneously. The probability that the product of the numbers appearing on the top faces of the dice is a perfect square is

  1. $\frac{1}{9}$
  2. $\frac{2}{9}$
  3. $\frac{1}{3}$
  4. $\frac{4}{9}$
in Numerical Ability by Boss (45.8k points)
edited by | 48 views
Migrated from GO Civil 2 months ago by Arjun

2 Answers

+2 votes
Best answer

When two dices are thrown simultaneously, the total number of combinations of the number that will be shown on faces of both the dices is given by,







$\implies$ Squares of all integers are known as perfect squares.


$\implies P(E)=\dfrac{8}{36}=\dfrac{2}{9}$

So$,(B)$ is the correct answer.

by Boss (45.8k points)
selected by
+2 votes
The answer is

(b). 2/9

This is because the favorable outcomes are :- (1,1),(2,2),(3,3),(4,4),(5,5),(6,6),(4,1),(1,4) = 8

total outcomes are = 36

P(product of numbers are perfect squares) = favorable outcomes / total outcomes = 8/36.

 On simplifying we get 2/9 as the answer.
by (147 points)

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