$A-2,B-4,C-6,D-8,{\color{Magenta}{E-10} },F-12,G-14,H-16,$
$I-18,{\color{Magenta}{J-20} },K-22,L-24,M-26,N-28,{\color{Magenta}{O-30} },$
${\color{Red}{P-32} },Q-34,R-36,{\color{Red}{S-38} },{\color{Magenta}{T-40} },U-42,V-44,$
$W-46,X-48,Y-50,Z-52$
So, $P+E+S+T=32+10+38+40=120$
Correct answer is $(C).$