in Analytical Aptitude edited by
2,157 views
6 votes
6 votes

Fatima starts from point $P$, goes North for $3$ km, and then East for $4$ km to reach point $Q$. She then turns to face point $P$ and goes $15$ km in that direction. She then goes North for $6$ km. How far is she from point $P$, and in which direction should she go to reach point $P$?

  1. $\text{8 km, East}$
  2. $\text{12 km, North}$
  3. $\text{6k m, East}$
  4. $\text{10 km, North}$
in Analytical Aptitude edited by
by
2.2k views
Migrated from GO Electronics 3 years ago by Arjun

2 Comments

8 km towards east.
0
0
can anyone please answer this question????
0
0

1 Answer

6 votes
6 votes
Best answer

Fatima traverses like this:-

 

Making right angle triangles, $\unicode{0x25FA} \: PXQ$ & then $ \unicode{0x25FA} \: PZY$. 

So, to reach point $P$ from $Y$ she has to travel =$\sqrt{(10^2-6^2)} = 8 \: km$. (in East direction)

Hence, Correct Answer: $ A. \: 8 \: km, \: East $

selected by

4 Comments

edited by

@chirudeepnamini @Shubhm

 In $\Delta QPX \:\text{&}\:\Delta PYZ$,

$\frac{QP}{PY}=\frac{PX}{YZ}=\frac{1}{2}$

&, $\angle QPX=\angle PYZ$ {$\because$ corresponding angles of two parallel lines XP & ZY}

$\therefore$ $\Delta QPX \:\text{&}\:\Delta PYZ$ are similar (from $\text{SAS}$ similarity).

thus, angles of similar triangles are same.

So,  $\angle YZP=\angle PXQ = 90^\circ$


Also, similar triangles have proportional sides,

so, $\frac{QP}{PY}=\frac{PX}{YZ}=\frac{XQ}{ZP}$

=>$\frac{XQ}{ZP}=\frac{1}{2}$

=> $ZP=8\:Km$.

6
6

@Naveen Kumar 3 thank you.. got it now..

1
1
None of the options says, NW, NE, SW, or SE this is a strong indication that point Z and point P are on the same level.
0
0
Answer:

Related questions