$$\underbrace{\underline{}\;\underline{}\;\underline{}}_{3!\text{ ways}}\;\boxed{\underline{S}\;\underline{R}}$$
As positions of $R$ and $S$ are fixed at first and second from right, so $ P, Q,$ and $T$ can be arranged in three possible places.
Hence, the total possible arrangements $={3!}=6$
Correct option is $(B).$