4 votes 4 votes Five numbers $10,7,5,4$ and $2$ are to be arranged in a sequence from left to right following the directions given below: No two odd or even numbers are next to each other. The second number from the left is exactly half of the left-most number. The middle number is exactly twice the right-most number. Which is the second number from the right? $2$ $4$ $7$ $10$ Analytical Aptitude gate2019-in general-aptitude analytical-aptitude logical-reasoning + – Arjun asked Feb 10, 2019 • edited May 30, 2019 by Pooja Khatri Arjun 3.8k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 3 votes 3 votes No two odd or even numbers are next to each other. The second number from the left is exactly half of the left-most number. So, the left most number must be even and its half must be odd which comes next. Only options are $10,5$ The middle number is exactly twice the right-most number. Middle number must be even and only options left are $2$ and $4$. Since $1$ is not there, $4$ must be the middle and $2$ the right most. Thus we get $$10\quad 5 \quad 4 \quad 7 \quad 2$$ Required answer is $7.$ Option C. Arjun answered Jun 2, 2019 • edited Jan 29, 2020 by KUSHAGRA गुप्ता Arjun comment Share Follow See 1 comment See all 1 1 comment reply mani312 commented Feb 5, 2021 reply Follow Share Actually to answer the question, statement 1 and 2 are sufficient 2 votes 2 votes Please log in or register to add a comment.
0 votes 0 votes From the above possible instructions, the sequence possible is:- 10,5,4,7,2. So, the answer is:- 7 Setika Mehra answered Nov 13, 2020 Setika Mehra comment Share Follow See all 0 reply Please log in or register to add a comment.