edited by
2,107 views
3 votes
3 votes

Given two sets $X=\{1,2,3\}$ and $Y=\{2,3,4\},$ we construct a set $Z$ of all possible fractions where the numerators belong to set $X$ and the denominators belong to set $Y.$ The product of elements having minimum and maximum values in the set $Z$ is _____.

  1. $1/12$
  2. $1/8$
  3. $1/6$
  4. $3/8$ 
edited by
Migrated from GO Electrical 4 years ago by Arjun

1 Answer

Best answer
5 votes
5 votes

Answer D.

For minimum value pick the smallest value from $X$ as numerator and largest value from $Y$ as denominator
$\implies $Minimum value $=\frac{1}{4}$

For maximum value pick the largest value from $X$ as numerator and smallest value from $Y$ as denominator
$\implies$ Maximum value $=\frac{3}{2}$

Their product = $\frac{1}{4}\times \frac{3}{2}=\frac{3}{8}$

selected by
Answer:

Related questions

8 votes
8 votes
2 answers
2
Arjun asked Feb 12, 2019
3,568 views
How many integers are there between $100$ and $1000$ all of whose digits are even?$60$$80$$100$$90$
4 votes
4 votes
3 answers
3
Arjun asked Feb 12, 2019
2,236 views
It takes two hours for a person $X$ to mow the lawn. $Y$ can mow the same lawn in four hours. How long (in minutes) will it take $X$ and $Y,$ if they work together to mow...
6 votes
6 votes
2 answers
4
Arjun asked Feb 12, 2019
4,002 views
The missing number in the given sequence $343,1331,$_____$,4913$ is$3375$$2744$$2197$$4096$