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An unbiased coin is tossed six times in a row and four different such trials are conducted. One trial implies six tosses of the coin. If H stands for head ans T stands for tail, the following are the observations from the four trials.

1. HTHTHT
2. TTHHHT
3. HTTHHT
4. HHHT_ _

Which statement describing the last two coin tosses of the fourth trial has the highest probability of being correct?

1. Two T will occur.
2. One H and one T will occur.
3. Two H will occur.
4. One H will be followed by one T.

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Migrated from GO Mechanical 5 months ago by Arjun

The outcome of a coin toss is independent of the previous outcomes - so no need to look into history.

Possible Outcomes:

1. $H H$
2. $H T$
3. $T H$
4. $T T$
1. $P(2T) = P(T T) = 1/4 = 0.25$
2. $P(1H \text{ AND } 1T) = P(H T) + P(T H) = 1/4 + 1/4 =0.25 + 0.25 = 0.5$
3. $P(2H) = P(H H) = 1/4 = 0.25$
4. $P(H T) = 1/4 = 0.25$

$0.5 > 0.25,$ So B is Correct 😊

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