@Arjun sir

After getting $y_{b}=-1$ by putting $x=1$, how we are concluding that B is the option.

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11 votes

Which of the following functions describe the graph shown in the below figure?

- $y=\mid \mid x \mid + 1 \mid -2$
- $y=\mid \mid x \mid - 1 \mid -1$
- $y=\mid \mid x \mid + 1 \mid -1$
- $y=\mid \mid x - 1 \mid -1 \mid$

Migrated from GO Mechanical 3 years ago by Arjun

10 votes

edited
Jan 1, 2020
by Lakshman Patel RJIT

When we put $x = 1,$ then option $(B)$ given $ y = -1$

When we put $x = -1,$ then option $(B)$ given $ y = -1$

When we put $x = 0,$ then option $(B)$ given $ y = 0$

When we put $x = 2,$ then option $(B)$ given $ y = 0$

When we put $x = -2,$ then option $(B)$ given $ y = 0$

When we put $x = 3,$ then option $(B)$ given $ y = 1$

When we put $x = -3,$ then option $(B)$ given $ y = 1$

Only Option $(B)$ satisfies the given graph.

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