In option, A relation can be clearly divided into AB and BC which would be both dependency preserving as well as in BCNF.
option B is already in BCNF .
option C has no BCNF decomposition that can preserve dependencies because to satisfy AB->C you will need all three attributes in relation which in turn will create C->A dependency which would violate BCNF normal form
example :- one possible decomposition that is in BCNF is AC and BC but this does not satisfy AB->C dependency.
So answer should be option C.