edited by
1,966 views
1 votes
1 votes
A 32-bit computer has two selector channels and one multiplexor channel. Each selector channel supports two magnetic disk and two magnetic tape units. The multiplexor channel has two line printers, two card readers, and ten VDT terminals connected to it. Assume the following transfer rates:
                                                                       Disk drive                             800 Kbytes/s
                                                                       Magnetic tape drive           200 Kbytes/s

                                                                       Line printer                          6.6 Kbytes/s
                                                                       Card reader                         1.2 Kbytes/s
                                                                       VDT                                       1 Kbytes/s
Estimate the maximum aggregate I/O transfer rate in this system
edited by

2 Answers

1 votes
1 votes
Selector transfer rate= max {800, 200}=800 KBps

multiplexer transfer rate= 2*6.6 + 2*1.2 + 10*1 = 13.2 + 2.4 + 10 =25.6 KBps

maximum rate=(no of select line) * 800 + (no of Multiplexer ) * 25.6 = 2*800 + 1*25.6=1600+25.6=1625.6 KBps
0 votes
0 votes
$1$ selector channel can transfer data at a time. Both cannot be active at a time

$1$ selector channel supports $=2\times 800+2\times 200+2\times 6.6+2\times 1.2+10\times 1$

$=1600+400+13.2+2.4+10=2025.6KB/sec$

Related questions

0 votes
0 votes
1 answer
1
aditi19 asked Jun 5, 2019
9,103 views
Consider a 4-drive, 200GB-per-drive RAID array. What is the available data storage capacity for each of the RAID levels, 0, 1, 3, 4, 5, and 6?