24 votes 24 votes If $\dfrac{(2y+1)}{(y+2)} < 1,$ then which of the following alternatives gives the CORRECT range of $y$ ? $- 2 < y < 2$ $- 2 < y < 1$ $- 3 < y < 1$ $- 4 < y < 1$ Quantitative Aptitude quantitative-aptitude gate2011-mn algebra + – Akash Kanase asked Dec 19, 2015 edited Dec 4, 2017 by pavan singh Akash Kanase 3.2k views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply stdntlfe commented Sep 22, 2017 reply Follow Share (2y+1)/(y+2)<1 sol. 2y+1<y+2 y<1 upper limit and you cant put y=-2 because it makes it infinite so range of y is -2<y<1 option B is the Right answer 0 votes 0 votes Hira Thakur commented Jan 10, 2023 reply Follow Share Option A) is wrong here, for $y=1,1<1=f$ options C, D) for $y=-2$ condition is false. option B) is correct. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Ans => B) - 2 < y < 1 Akash Kanase answered Dec 19, 2015 Akash Kanase comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes -2 gives not determined so y cannot be -3 , -4 as they will include -2 in there range, now from a and b . putting y=1 gives 1. as stated it should be less than 1 so B is the correct answer Tendua answered Dec 19, 2015 Tendua comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes while solving inequalities, the direction of inequality doesn’t change when a number is added or subtracted on both sides when a positive number is multiplied or divided on both sides changes when a negative number is multiplied or divided on both sides $\therefore$ The answer is option $\LARGE B$ subbus answered Jun 13, 2021 edited Jun 13, 2021 by subbus subbus comment Share Follow See all 0 reply Please log in or register to add a comment.