# GATE2011 MN: GA-63

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$L, M$ and $N$ are waiting in a queue meant for children to enter the zoo. There are $5$ children between $L$ and $M$, and $8$ children between $M$ and $N$. If there are $3$ children ahead of $N$ and $21$ children behind $L$, then what is the minimum number of children in the queue?

1. $28$
2. $27$
3. $41$
4. $40$

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21L5M8N3 For follow the sequence of the queue there are 40 students are there.
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15---M--5--L--2--N--3    so total 28
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If in case of maximum children then 40

$L, M$ and $N$ are waiting in queue that are meant for children, so they are also counted as children.

Correct Answer: $A$

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thanks praveen sir
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18 N 2 L 5 M

18+2+5=35

25+L,M,N=28

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