$L1 \cup L2 = (L1'\cap L2')'$
Let L1 is DCFL then L1' is also DCFL
Let L2 is Regular then L2' is also Regular
$L1'\cap L2'$ is DCFL since any language intersection with regular language is always the language
so $(L1'\cap L2')'$ is DCFL as complement of DCFL is DCFL
$L1 \cup L2 $ is DCFL