menu
search
Log In
Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true

Subjects

Network Sites

 GO Mechanical
 GO Electrical
 GO Electronics
 GO Civil
 CSE Doubts

Peter Linz Edition 4 Exercise 7.4 Question 5 (Page No. 204)

0 votes
27 views
Show that any LL grammar is unambiguous.
in Theory of Computation 27 views

Please log in or register to answer this question.

← Prev. Next →
← Prev. Qn. in Sub. Next Qn. in Sub. →

Related questions

0 votes
0 answers
1
72 views
Peter Linz Edition 4 Exercise 7.4 Question 9 (Page No. 204)
Give LL grammars for the following languages, assuming $Σ =$ {$a,b, c$}. (i) $L=$ {$a^nb^mc^{n+m}:n\geq0,m\geq0$} . (ii) $L=$ {$a^{n+2}b^mc^{n+m}:n\geq0,m\geq0$} . (iii) $L=$ {$a^nb^{n+2}c^{m}:n\geq0,m\gt1$} . (iv) $L=$ {$w:n_a(w)\lt n_b(w)$} . (v) $L=$ {$w:n_a(w)+n_b(w)\neq n_c(w)$} .
Give LL grammars for the following languages, assuming $Σ =$ {$a,b, c$}. (i) $L=$ {$a^nb^mc^{n+m}:n\geq0,m\geq0$} . (ii) $L=$ {$a^{n+2}b^mc^{n+m}:n\geq0,m\geq0$} . (iii) $L=$ {$a^nb^{n+2}c^{m}:n\geq0,m\gt1$} . (iv) $L=$ {$w:n_a(w)\lt n_b(w)$} . (v) $L=$ {$w:n_a(w)+n_b(w)\neq n_c(w)$} .
asked Jun 25, 2019 in Theory of Computation Naveen Kumar 3 72 views
Dark theme
Muffin by Hélio Chun
Thanks to Q2A
...