What percentage $(\%)$ of the IPv4, IP address space do all class C addresses consume?
Class C Addresses
Total No. of IpV4 addresses possible = $ 2^(32) $
Total No of IPv4 address belong to Class C =$ 2^(29)$ [As Class C IP addresses always start with 1 1 0 ]
So,required Percentage = ( 2^29 / 2^32 ) X 100
Let, N denotes Network part and H denotes host part
CLASS C ,
Octect Format : N.N.N.H
i.e. 24 bits for Network Part and 8 bits for host part.
But out of 24 bits , first three bits are fixes which is 110,
So, percentage (%) of the IPv4, IP address space do all class C addresses consume = (2^29/2^32)*100 %
= 1/8*100 %