edited by
8,956 views

4 Answers

6 votes
6 votes
ans is option 2

class B default net mask 255.255.0.0  (11111111  11111111  00000000  00000000)

to have 500 subnets  9 more bits are required to be included in subnet mask  

so subnet mask will be 255.255.255.128  ( 11111111  11111111  11111111  10000000)

each subnet mask has 7 bits for host-part   which are sufficient for 100 hosts
0 votes
0 votes

In class B network the first 16 bits will be the network id and the rest of the bits will be for the host ids.

In subnetting the host id is further borrowed.for 500 subnets to be possible at least 9 bits should be borrowed from the host id part.when 9 bits are borrowed from the host id atmost 510 subnets will be possible.

From the rest of the 7 bits 126 hosts will be possible for each subnet.

Therefore option (b) is correct

0 votes
0 votes
The answer will be b) as here bo.of subnets is $2^9$

No. of bits in network id = 8+8+8+1 =25 and the rest 7 bits are host if will will be $2^7$. so we can have upto 512 subnets and each subnet can have upto 128 hosts
Answer:

Related questions

3 votes
3 votes
4 answers
2
Arjun asked Jul 2, 2019
3,211 views
What is the name of the protocol that allows a client to send a broadcast message with its MAC address and receive an IP address in reply?ARPDNSRARPICMP