2 votes 2 votes You are designing a link layer protocol for a link with bandwidth of $1$ Gbps ($10^9$ bits/second) over a fiber link with length of $800$ km. Assume the speed of light in this medium is $200000$ km/second. What is the propagation delay in this link? $1$ millisecond $2$ milliseconds $3$ milliseconds $4$ milliseconds Computer Networks ugcnetcse-june2019-paper2 propagation-delay + – Arjun asked Jul 2, 2019 • edited Jul 24, 2019 by Lakshman Bhaiya Arjun 6.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Propagation delay : Time taken by the first bit to travel from sender to receiver end of the link. Propagation delay = distance/transmission speed = d/s Propagation delay = 800km/200000km/sec =4ms Aman_Singh answered Jul 4, 2019 Aman_Singh comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 1 sec =1000 mil sec and propagation delay=distance/velocity here distance=800 km and velocity=200000 km/sec so, Tp=800/200000=1/250 sec 1/250 *1000=4 mil sec dibyendu_007 answered Sep 10, 2019 dibyendu_007 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Propagation delay : Time taken by the first bit to travel from sender to receiver end of the link. Propagation delay = distance/speed of the medium = d/s Propagation delay = 800km/200000km/sec =(800/200000)sec =(800/200)milliseconds =4 milliseconds scholaraniket answered Sep 11, 2019 scholaraniket comment Share Follow See all 0 reply Please log in or register to add a comment.