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For a real number $t >0$, let $\sqrt{t}$ denote the positive square root of $t$. For a real number $x > 0$, let $F(x)= \int_{x^{2}}^{4x^{2}} \sin \sqrt{t} dt$. If $F'$ is the derivative of $F$, then

1. $F'(\frac{\pi}{2}) = 0$
2. $F'(\frac{\pi}{2}) = \pi$
3. $F'(\frac{\pi}{2}) = - \pi$
4. $F'(\frac{\pi}{2}) = 2\pi$
asked in Calculus | 94 views

Ans is c...

+1 vote
Option C
answered by (109 points)

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