The Gateway to Computer Science Excellence
First time here? Checkout the FAQ!
x
+2 votes
61 views

Let $n \in \mathbb{N}$ be a six digit number whose base $10$ expansion is of the form $abcabc$, where $a, b, c$  are digits between $0$ and $9$ and $a$ is non-zero. Then,

  1. $n$ is divisible by $5$
  2. $n$ is divisible by $8$
  3. $n$ is divisible by $13$
  4. $n$ is divisible by $17$
in Numerical Ability by Boss (29.7k points) | 61 views

1 Answer

+2 votes
Best answer
i think c will be the answer. Just do the expansion. The number wil be divisible if and only if every term is divisible or it satisfy the divisiblity rule. but as not much information is given just head on doing the expansion and adding .

$10^5 a + 10^4 b + 10^3 c + 10^2 a + 10^1 b + 10^ 0 c$

so after adding it will be something like . 100100a + 10010b + 1001c. all terms are divisible by 13 so option C
by Boss (15.9k points)
selected by

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,339 questions
55,763 answers
192,337 comments
90,771 users