We know that in demand paging EMAT is: P*S+(1-P)*M
P = Page Fault Rate (Whenever frame is not found in Main memory then bring from secondary mem to main mem)
S = Page Fault Service Time (Time to transfer data from sec mem to main mem)
(1-P) = No page fault (TLB Contain page->frame mapping OR TLB don't contain page->frame mapping)
So by understanding the above statements we can evaluate using the data given:
EMAT: = P*S+(1-P)*M + 100(avg exec time)
$10^{-4}$ * 8 * $10^{-3}$ + (1-$10^{-4}$)(TLB HIT + TLB MISS) + 100
800 + 0.9999(0.9*(2*150) + 0.1(6*150)) + 100
800 + 0.9999(270+90) + 100
800 + 359.964 + 100 = 1259.964 = 1260ns