Let $f(x)=(x-1)(x-2)(x-3)g(x); \: x\in \mathbb{R}$ where $g$ is twice differentiable function. Then
- there exists $y\in(1,3)$ such that $f’’(y)=0.$
- there exists $y\in(1,2)$ such that $f’’(y)=0.$
- there exists $y\in(2,3)$ such that $f’’(y)=0.$
- none of the above is true.