2 votes 2 votes Let $A=\begin{pmatrix} 1 & 1 & 0\\ 0 & a & b\\1 & 0 & 1 \end{pmatrix}$. Then $A^{-1}$ does not exist if $(a,b)$ is equal to $(1,-1)$ $(1,0)$ $(-1,-1)$ $(0,1)$ Linear Algebra isi2018-dcg linear-algebra matrix inverse + – gatecse asked Sep 18, 2019 • recategorized Nov 19, 2019 by Lakshman Bhaiya gatecse 510 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes A matrix is not invertible if it's determinant is $0.$ $|A|= 1(a-0)-1(0-b)= a+b$ Only Option A) satisfies Ashwani Kumar 2 answered Sep 20, 2019 • edited Nov 19, 2019 by Lakshman Bhaiya Ashwani Kumar 2 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Option A satisfies the condition when we calculate the determinant we get a+b = 0 equation. eshita1997 answered May 6, 2021 eshita1997 comment Share Follow See all 0 reply Please log in or register to add a comment.