Register

ISI2018-DCG-15

• recategorized by
477 views
1 votes
1 votes

The number of parallelograms that can be formed from a set of four parallel lines intersecting another set of three parallel lines is

  1. $6$
  2. $9$
  3. $12$
  4. $18$
• recategorized by
User Avatar

1 Answer

2 votes
2 votes
Answer $D$

Total number of parallel lines $= 4$

Total number of intersecting lines$ = 3$

$\therefore$ Total number of parallelograms possible $$=\binom{4}{2} \times \binom{3}{2} = 6 \times 3 = 18$$

$\therefore D$ is the correct option.
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

3 votes
3 votes
2 answers
1
gatecse asked Sep 18, 2019
712 views
ISI2018-DCG-1
The digit in the unit place of the number $7^{78}$ is $1$ $3$ $7$ $9$
The digit in the unit place of the number $7^{78}$ is$1$$3$$7$$9$
User Avatar
2 votes
2 votes
1 answer
2
gatecse asked Sep 18, 2019
524 views
ISI2018-DCG-30
Let $0.01^x+0.25^x=0.7$ . Then $x\geq1$ $0\lt x\lt1$ $x\leq0$ no such real number $x$ is possible.
Let $0.01^x+0.25^x=0.7$ . Then$x\geq1$$0\lt x\lt1$$x\leq0$no such real number $x$ is possible.
User Avatar
4 votes
4 votes
1 answer
3
gatecse asked Sep 18, 2019
779 views
ISI2018-DCG-2
If $P$ is an integer from $1$ to $50$, what is the probability that $P(P+1)$ is divisible by $4$? $0.25$ $0.50$ $0.48$ none of these
If $P$ is an integer from $1$ to $50$, what is the probability that $P(P+1)$ is divisible by $4$?$0.25$$0.50$$0.48$none of these
User Avatar
0 votes
0 votes
1 answer
4
gatecse asked Sep 18, 2019
503 views
ISI2018-DCG-3
If the co-efficient of $p^{th}, (p+1)^{th}$ and $(p+2)^{th}$ terms in the expansion of $(1+x)^n$ are in Arithmetic Progression (A.P.), then which one of the following is true? $n^2+4(4p+1)+4p^2-2=0$ $n^2+4(4p+1)+4p^2+2=0$ $(n-2p)^2=n+2$ $(n+2p)^2=n+2$
If the co-efficient of $p^{th}, (p+1)^{th}$ and $(p+2)^{th}$ terms in the expansion of $(1+x)^n$ are in Arithmetic Progression (A.P.), then which one of the following is ...
User Avatar
Link Copied!