1 votes 1 votes If $f(x)=e^{5x}$ and $h(x)=f’’(x)+2f’(x)+f(x)+2$ then $h(0)$ equals $38$ $8$ $4$ $0$ Calculus isi2017-dcg calculus differentiation functions + – gatecse asked Sep 18, 2019 recategorized Nov 15, 2019 by Lakshman Bhaiya gatecse 325 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes $f(x)=e^{5x}$ $f'(x)=5e^{5x}$ $f''(x)=25 e^{5x}$ $h(x)=25 e^{5x} + 10 e^{5x} + e^{5x} +2$ $h(0)= 25+10+1+2=38$ Option A) Ashwani Kumar 2 answered Sep 20, 2019 Ashwani Kumar 2 comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Answer : Option (A) $ f(x) = e^{5x}$ Differentiating wrt. x, $f'(x) = 5 \cdot e^{5x}$ Differentiating wrt. x, $f''(x) = 5 \cdot 5 \cdot e^{5x} = 25 \cdot e^{5x}$ Thus, anwer will be $25 \cdot e^{0} + 10 \cdot e^0 + e^0 + 2 = 38$ toxicdesire answered Sep 20, 2019 toxicdesire comment Share Follow See all 0 reply Please log in or register to add a comment.