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ISI2017DCG13
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The value of $\dfrac{x}{1x^2} + \dfrac{x^2}{1x^4} + \dfrac{x^4}{1x^8} + \dfrac{x^8}{1x^{16}}$ is
$\frac{1}{1x^{16}}$
$\frac{1}{1x^{12}}$
$\frac{1}{1x} – \frac{1}{1x^{16}}$
$\frac{1}{1x} – \frac{1}{1x^{12}}$
isi2017dcg
numericalability
summation
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Sep 18, 2019
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Numerical Ability
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gatecse
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Nov 15, 2019
by
Lakshman Patel RJIT

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