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ISI2017-DCG-13

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Adding and Subtracting 1 on each term

$S= \frac{1+x -1}{1-x^{2}}+\frac{1+x^{2} -1}{1-x^{4}}+\frac{1+x^{4} -1}{1-x^{8}}+\frac{1+x^{8} -1}{1-x^{16}}$

Using $(a^{2}-b^{2})=(a+b)(a-b)$

$S=\frac{1}{1-x}-\frac{1}{1-x^{2}}+\frac{1}{1-x^{2}}-\frac{1}{1-x^{4}}+\frac{1}{1-x^{4}}-\frac{1}{1-x^{8}}+\frac{1}{1-x^{8}}-\frac{1}{1-x^{16}}$

Simplifies to $S = \frac{1}{1-x} - \frac{1}{1-x^{16}}$

Answer: C

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