Two sets have $m$ and $n$ elements. The number of subsets of the first set is $96$ more than that of the second set. Then the values of $m$ and $n$ are
Option C) is correct
Number of subsets of both the set = $2^m, 2^n$ respectively
According to question:
$2^m = 96+2^n$
$2^m - 2^n = 96$
Only Option c) satisfies $2^7-2^5=128-32= 96$