0 votes 0 votes Two sets have $m$ and $n$ elements. The number of subsets of the first set is $96$ more than that of the second set. Then the values of $m$ and $n$ are $8$ and $6$ $7$ and $6$ $7$ and $5$ $6$ and $5$ Set Theory & Algebra isi2017-dcg set-theory + – gatecse asked Sep 18, 2019 recategorized Nov 15, 2019 by Lakshman Bhaiya gatecse 379 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Option C) is correct Number of subsets of both the set = $2^m, 2^n$ respectively According to question: $2^m = 96+2^n$ $2^m - 2^n = 96$ Only Option c) satisfies $2^7-2^5=128-32= 96$ Ashwani Kumar 2 answered Sep 21, 2019 Ashwani Kumar 2 comment Share Follow See all 0 reply Please log in or register to add a comment.