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Two sets have $m$ and $n$ elements. The number of subsets of the first set is $96$ more than that of the second set. Then the values of $m$ and $n$ are

  1. $8$ and $6$
  2. $7$ and $6$
  3. $7$ and $5$
  4. $6$ and $5$
in Others by Boss (16.3k points)
edited by | 3 views

1 Answer

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Option C) is correct

Number of subsets of both the set = $2^m, 2^n$ respectively 

According to question:

$2^m = 96+2^n$

$2^m - 2^n = 96$

Only Option c) satisfies $2^7-2^5=128-32= 96$

by Boss (15.4k points)

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