35 views

Two sets have $m$ and $n$ elements. The number of subsets of the first set is $96$ more than that of the second set. Then the values of $m$ and $n$ are

1. $8$ and $6$
2. $7$ and $6$
3. $7$ and $5$
4. $6$ and $5$

recategorized | 35 views

Option C) is correct

Number of subsets of both the set = $2^m, 2^n$ respectively

According to question:

$2^m = 96+2^n$

$2^m - 2^n = 96$

Only Option c) satisfies $2^7-2^5=128-32= 96$

by Boss

+1 vote