The Gateway to Computer Science Excellence
First time here? Checkout the FAQ!
x
0 votes
3 views

Two sets have $m$ and $n$ elements. The number of subsets of the first set is $96$ more than that of the second set. Then the values of $m$ and $n$ are

  1. $8$ and $6$
  2. $7$ and $6$
  3. $7$ and $5$
  4. $6$ and $5$
in Others by Boss (16.3k points)
edited by | 3 views

1 Answer

0 votes

Option C) is correct

Number of subsets of both the set = $2^m, 2^n$ respectively 

According to question:

$2^m = 96+2^n$

$2^m - 2^n = 96$

Only Option c) satisfies $2^7-2^5=128-32= 96$

by Boss (15.4k points)

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,339 questions
55,765 answers
192,354 comments
90,815 users