Register

ISI2017-DCG-4

• recategorized by
445 views

1 Answer

1 votes
1 votes
since A^3 -A^2 +A+I =0

then A^3 -A^2 +A= I

=> A(A^2 -A + I)= I

=> A=I

so A^4= I^4=I

=> A^4= I
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

2 votes
2 votes
2 answers
1
gatecse asked Sep 18, 2019
539 views
ISI2017-DCG-7
If $\begin{vmatrix} 10! & 11! & 12! \\ 11! & 12! & 13! \\ 12! & 13! & 14! \end{vmatrix} = k(10!)(11!)(12!)$, then the value of $k$ is $1$ $2$ $3$ $4$
If $\begin{vmatrix} 10! & 11! & 12! \\ 11! & 12! & 13! \\ 12! & 13! & 14! \end{vmatrix} = k(10!)(11!)(12!)$, then the value of $k$ is$1$$2$$3$$4$
User Avatar
1 votes
1 votes
1 answer
2
gatecse asked Sep 18, 2019
585 views
ISI2017-DCG-25
If $f(x) = \begin{vmatrix} 2 \cos ^2 x & \sin 2x & – \sin x \\ \sin 2x & 2 \sin ^2 x & \cos x \\ \sin x & – \cos x & 0 \end{vmatrix},$ then $\int_0^{\frac{\pi}{2}} [ f(x) + f’(x)] dx$ is $\pi$ $\frac{\pi}{2}$ $0$ $1$
If $f(x) = \begin{vmatrix} 2 \cos ^2 x & \sin 2x & – \sin x \\ \sin 2x & 2 \sin ^2 x & \cos x \\ \sin x & – \cos x & 0 \end{vmatrix},$ then $\int_0^{\frac{\pi}{2}} [...
User Avatar
3 votes
3 votes
2 answers
3
gatecse asked Sep 18, 2019
564 views
ISI2017-DCG-1
The value of $\dfrac{1}{\log_2 n}+ \dfrac{1}{\log_3 n}+\dfrac{1}{\log_4 n}+ \dots + \dfrac{1}{\log_{2017} n}\:\:($ where $n=2017!)$ is $1$ $2$ $2017$ none of these
The value of $\dfrac{1}{\log_2 n}+ \dfrac{1}{\log_3 n}+\dfrac{1}{\log_4 n}+ \dots + \dfrac{1}{\log_{2017} n}\:\:($ where $n=2017!)$ is$1$$2$$2017$none of these
User Avatar
0 votes
0 votes
2 answers
4
gatecse asked Sep 18, 2019
405 views
ISI2017-DCG-2
The area of the shaded region in the following figure (all the arcs are circular) is $\pi$ $2 \pi$ $3 \pi$ $\frac{9}{8} \pi$
The area of the shaded region in the following figure (all the arcs are circular) is$\pi$$2 \pi$$3 \pi$$\frac{9}{8} \pi$
User Avatar
Link Copied!