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Answer: $\mathbf C$

Explanation:

Group the vowels together and make it a single packet $= \mathbf {OUE}$

Rest of the words are: $\mathbf {CMPTR}$


$\therefore$ Total words to be grouped including one packet $ = \mathbf {\underbrace{(OUE)}_\text{=3!}CMPTR} = 6!3!$
$\therefore$ Answer $ = \mathbf {3!6!}$


$\therefore \mathbf C$ is the correct option.

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