The Gateway to Computer Science Excellence
+2 votes
10 views

If the letters of the word $\text{COMPUTER}$ be arranged in random order, the number of arrangements in which the three vowels $O, U$ and $E$ occur together is

  1. $8!$
  2. $6!$
  3. $3!6!$
  4. None of these
in Combinatory by Boss (16.8k points)
recategorized by | 10 views

1 Answer

+1 vote

Answer: $\mathbf C$

Explanation:

Group the vowels together and make it a single packet $= \mathbf {OUE}$

Rest of the words are: $\mathbf {CMPTR}$


$\therefore$ Total words to be grouped including one packet $ = \mathbf {\underbrace{(OUE)}_\text{=3!}CMPTR} = 6!3!$
$\therefore$ Answer $ = \mathbf {3!6!}$


$\therefore \mathbf C$ is the correct option.

by Boss (13.2k points)
edited by

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,647 questions
56,492 answers
195,439 comments
100,696 users