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The total number of factors of $3528$ greater than $1$ but less than $3528$ is

  1. $35$
  2. $36$
  3. $34$
  4. None of these
in Numerical Ability by Boss (17.5k points)
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1 Answer

+1 vote

Answer: $\mathbf{C}$

The total number of factors is given by:

$\mathrm {N= (a+1)(b+1)(c+1)}$ where $\mathbf a$, $\mathbf b$, and $\mathbf c$ are the powers of the prime factors.

So, $3528$ can be written as $2^33^27^2$

$\Rightarrow \mathrm { a = 3, b =2, c = 2}$

 $=\mathrm {(a+1)(b+1)(c+1) = 4.3.3 = 36}$

But we have to remove the factors $1$ and $3528$ (as given in the question)

$\therefore$ Total number of factors $=36-2 = 34$

$\therefore \mathbf C $ is the correct option.

by Boss (19.1k points)
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