1 votes 1 votes The value of $$\begin{vmatrix} 1 & \log _x y & \log_x z \\ \log _y x & 1 & \log_y z \\ \log _z x & \log _z y & 1 \end{vmatrix}$$ is $0$ $1$ $-1$ None of these Linear Algebra isi2015-dcg linear-algebra determinant + – gatecse asked Sep 18, 2019 recategorized Nov 14, 2019 by Lakshman Bhaiya gatecse 479 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes First row: logx/logx , logy/logx , logz/logx. Take 1/logx out then frist row will be logx , logy, logz Similarly second and third row will become logx , logy . logz. As two rows are identical, so determinant =0 ayush.5 answered Oct 12, 2020 ayush.5 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Put x=y=z so answer is ZERO amit166 answered Sep 20, 2019 amit166 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes anyway solve you get answer = 0 which is option A indranil21 answered Sep 13, 2020 indranil21 comment Share Follow See all 0 reply Please log in or register to add a comment.