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The shaded region in the following diagram represents the relation

1. $y \leq x$
2. $\mid y \mid \leq \mid x \mid$
3. $y \leq \mid x \mid$
4. $\mid y \mid \leq x$

recategorized | 45 views

Y is +ve in 1st quardnent and -ve in 3rd quardnent and X is +ve in 1st and 3rd so mod(y) so

And=D
by

Answer: $\mathbf D$

Solution:

$|y|=x \Rightarrow x=-y,\; \forall y<0$

and, $x=y, \;\;\forall y>0$

The domain is $x >= 0\;\because$ the left side is non-negative.

So graph $y=x\;\;\forall x >= 0$, and $y=-x\;\;\forall x >= 0$ .

$\therefore \mathbf D$ is the right option.

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