0 votes 0 votes For all the natural number $n \geq 3, \: n^2+1$ is divisible by $3$ not divisible by $3$ divisible by $9$ None of these Quantitative Aptitude isi2015-dcg quantitative-aptitude number-system + – gatecse asked Sep 18, 2019 • recategorized Nov 13, 2019 by Lakshman Bhaiya gatecse 364 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes if we take $n=4$ then $n^2+1=17$ which is not divisible by $3$ and $9$. So option a and c are eliminated. Option B. is correct option. For proof refer this Satbir answered Sep 20, 2019 Satbir comment Share Follow See all 0 reply Please log in or register to add a comment.