Register

ISI2015-DCG-10

• recategorized by
424 views

1 Answer

0 votes
0 votes

For a number n in the series let x = n(n+1)/2 ...(1)

Here, x is the last position of the element n in the sequence.

A/q n(n+1)/2 = 5,000

 =>  n(n+1) = 10,000​ ; ​​​​​​which simply means n~100

Put n=100 in (1), 100(101)/2 = 5050 i.e. position of last 100 is 5050 and position of first 100 must be 5050 - (100 - 1) = 4951.

Therefore, form position 4951 to 5050 there are 100 100s, hence the correct answer is option C.

• edited by
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

2 votes
2 votes
4 answers
1
gatecse asked Sep 18, 2019
583 views
ISI2015-DCG-1
The sequence $\dfrac{1}{\log_3 2}, \: \dfrac{1}{\log_6 2}, \: \dfrac{1}{\log_{12} 2}, \: \dfrac{1}{\log_{24} 2} \dots $ is in Arithmetic progression (AP) Geometric progression ( GP) Harmonic progression (HP) None of these
The sequence $\dfrac{1}{\log_3 2}, \: \dfrac{1}{\log_6 2}, \: \dfrac{1}{\log_{12} 2}, \: \dfrac{1}{\log_{24} 2} \dots $ is inArithmetic progression (AP)Geometric progress...
User Avatar
1 votes
1 votes
4 answers
2
gatecse asked Sep 18, 2019
558 views
ISI2015-DCG-2
Let $S=\{6, 10, 7, 13, 5, 12, 8, 11, 9\}$ and $a=\underset{x \in S}{\Sigma} (x-9)^2$ & $b = \underset{x \in S}{\Sigma} (x-10)^2$. Then $a <b$ $a>b$ $a=b$ None of these
Let $S=\{6, 10, 7, 13, 5, 12, 8, 11, 9\}$ and $a=\underset{x \in S}{\Sigma} (x-9)^2$ & $b = \underset{x \in S}{\Sigma} (x-10)^2$. Then$a <b$$a>b$$a=b$None of these
User Avatar
0 votes
0 votes
2 answers
3
gatecse asked Sep 18, 2019
818 views
ISI2015-DCG-4
If $\tan x=p+1$ and $\tan y=p-1$, then the value of $2 \cot (x-y)$ is $2p$ $p^2$ $(p+1)(p-1)$ $\frac{2p}{p^2-1}$
If $\tan x=p+1$ and $\tan y=p-1$, then the value of $2 \cot (x-y)$ is$2p$$p^2$$(p+1)(p-1)$$\frac{2p}{p^2-1}$
User Avatar
1 votes
1 votes
1 answer
4
gatecse asked Sep 18, 2019
400 views
ISI2015-DCG-6
The coefficient of $x^2$ in the product $(1+x)(1+2x)(1+3x) \dots (1+10x)$ is $1320$ $1420$ $1120$ None of these
The coefficient of $x^2$ in the product $(1+x)(1+2x)(1+3x) \dots (1+10x)$ is$1320$$1420$$1120$None of these
User Avatar
Link Copied!