28 views

Let $G$ be a group with identity element $e$. If $x$ and $y$ are elements in $G$ satisfying $x^5y^3=x^8y^5=e$, then which of the following conditions is true?

1. $x=e, \: y=e$
2. $x\neq e, \: y=e$
3. $x=e, \: y \neq e$
4. $x\neq e, \: y \neq e$

recategorized | 28 views

Start with x5y3=x8y5x5y3=x8y5 and multiply it with x−5x−5 to the left and with y−3y−3 to the right. We get e=x3y2e=x3y2 and therefore x3y2=x5y3=ex3y2=x5y3=e By the same way we get to e=x2y=x3ye=x2y=x3y and again this yields x=ex=e Replacing in the initial identity we get y3=y5=ey3=y5=e and through the same approach we get to y=e
by (17 points)