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Suppose a solution of the differential equation $$(xy^3+x^2y^7)\frac{\mathrm{d} y}{\mathrm{d} x}=1,$$ satisfies the initial condition $y(1/4)=1$. Then the value of $\dfrac{\mathrm{d} y}{\mathrm{d} x}$ when $y=-1$ is

  1. $\frac{4}{3}$
  2. $- \frac{4}{3}$
  3. $\frac{16}{5}$
  4. $- \frac{16}{5}$
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