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In the Taylor expansion of the function $f(x)=e^{x/2}$ about $x=3$, the coefficient of $(x-3)^5$ is

1. $e^{3/2} \frac{1}{5!}$
2. $e^{3/2} \frac{1}{2^5 5!}$
3. $e^{-3/2} \frac{1}{2^5 5!}$
4. none of the above
in Calculus
recategorized | 10 views