1 votes 1 votes For non-negative integers $m$, $n$ define a function as follows $$f(m,n) = \begin{cases} n+1 & \text{ if } m=0 \\ f(m-1, 1) & \text{ if } m \neq 0, n=0 \\ f(m-1, f(m,n-1)) & \text{ if } m \neq 0, n \neq 0 \end{cases}$$ Then the value of $f(1,1)$ is $4$ $3$ $2$ $1$ Calculus isi2015-mma calculus functions non-gate + – Arjun asked Sep 23, 2019 • recategorized Nov 16, 2019 by Lakshman Bhaiya Arjun 523 views answer comment Share Follow See 1 comment See all 1 1 comment reply NastyBall commented Jun 17, 2021 reply Follow Share B is the correct answer. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes f(1,1)=f(0,f(1,0)) since m$\neq$0,n$\neq$0 =f(0,f(0,1)) since m$\neq$0,$n=0$ =f(0,2) since m$=$0 =3 since m$=$0 chirudeepnamini answered Oct 19, 2019 chirudeepnamini comment Share Follow See all 0 reply Please log in or register to add a comment.