0 votes 0 votes Let $$f(x) = \begin{cases}\mid \:x \mid +1, & \text{ if } x<0 \\ 0, & \text{ if } x=0 \\ \mid \:x \mid -1, & \text{ if } x>0. \end{cases}$$ Then $\underset{x \to a}{\lim} f(x)$ exists if $a=0$ for all $a \in R$ for all $a \neq 0$ only if $a=1$ Calculus isi2014-dcg calculus functions limits + – Arjun asked Sep 23, 2019 recategorized Nov 12, 2019 by Lakshman Bhaiya Arjun 351 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.