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$\underset{x \to 2}{\lim} \dfrac{1}{1+e^{\frac{1}{x-2}}}$  is

  1. $0$
  2. $1/2$
  3. $1$
  4. non-existent
in Calculus by Veteran (431k points)
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1 Answer

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Put x=2 in the power of e, we get e^(1/(2-2)) which is e^infinity which is infinity.. Now 1/(1+infinity) = 1/ infinity which is equal to zero. Hence answer is zero.
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