edited by
350 views
0 votes
0 votes

In Theorem $3.21$, we showed that a language is Turing-recognizable iff some enumerator enumerates it. Why didn’t we use the following simpler algorithm for the forward direction of the proof? As before, $s_{1}, s_{2},\dots $ is a list of all strings in $\Sigma^{\ast}.$
$E = "$ Ignore the input.

  1. Repeat the following for $i = 1,2,3,\dots.$
  2. Run $M$ on $s_{i}.$
  3. If it accepts, print out $s_{i}."$ 
edited by

Please log in or register to answer this question.

Related questions

0 votes
0 votes
0 answers
3