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Michael Sipser Edition 3 Exercise 4 Question 2 (Page No. 211)

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admin asked Oct 15, 2019
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Michael Sipser Edition 3 Exercise 4 Question 3 (Page No. 211)
Let $ALL_{DFA} = \{ \langle{ A }\rangle \mid A \text{ is a DFA and}\: L(A) = \Sigma^{\ast}\}.$ Show that $ALL_{DFA}$ is decidable.
Let $ALL_{DFA} = \{ \langle{ A }\rangle \mid A \text{ is a DFA and}\: L(A) = \Sigma^{\ast}\}.$ Show that $ALL_{DFA}$ is decidable.
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admin asked Oct 17, 2019
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Michael Sipser Edition 3 Exercise 4 Question 13 (Page No. 211)
Let $A = \{ \langle{ R, S \rangle} \mid \text{R and S are regular expressions and} \: L(R) \subseteq L(S)\}$. Show that $A$ is decidable.
Let $A = \{ \langle{ R, S \rangle} \mid \text{R and S are regular expressions and} \: L(R) \subseteq L(S)\}$. Show that $A$ is decidable.
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admin asked Oct 17, 2019
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Michael Sipser Edition 3 Exercise 4 Question 12 (Page No. 211)
Let $A = \{\langle{ M \rangle} \mid \text{M is a DFA that doesn’t accept any string containing an odd number of 1s}\}$.Show that $A$ is decidable.
Let $A = \{\langle{ M \rangle} \mid \text{M is a DFA that doesn’t accept any string containing an odd number of 1s}\}$.Show that $A$ is decidable.
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