3,304 views
4 votes
4 votes
a) lower line efficiency

b) higher line efficiency

c) no change in line efficiency

d) no relation between line efficiency and frame size

3 Answers

4 votes
4 votes
No change in line efficiency.

 

Line efficiency will increase , only when we have some hops between sender and receiver.

For this question we will consider that there is no hop between sender and receiver so , dividing a constant message in k frames or increase the number of frames to ( k+i),will not effect link utilization.
3 votes
3 votes
Efficiency should decrease,

efficiency= 1/ 1+ 2a where a = (d/v) * (B/ L) so when L increase B/L decrease that means (d/v) * (B/ L) is also decreasing.

d- distance, v- velocity, B- bandwidth, L - frame length.

Increase number of frames increase frame length L.

So , option A is correct.
0 votes
0 votes

yes i agree with you @Bikram if it was a normal case but keeping the message size constant 

let is divided into packets of lenght then L = n*l 

Transmission time = n*l / B which is equivalent to L / B

So no change in transmission time but there will be change in propogation time (P)

IN STOP AND WAIT – 

the propagation time will become = n*P So there will be low utilization 

IN sliding window protocol –

there will be no change in efficiency as it does not waste propogation time so n*P will be utilized anyway

Answer:

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