1 votes 1 votes A process running on $CTSS$ needs $30$ quanta to complete. How many times must it be swapped in, including the very first time (before it has run at all)? Operating System tanenbaum operating-system process-and-threads process-scheduling descriptive + – admin asked Oct 25, 2019 • edited Oct 25, 2019 by Lakshman Bhaiya admin 713 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Answer: The first time it receives 1 quantum. In the following execution, it receives $2, 4, 8, \text {and}\; 15$. Hence, it should be swapped $5$ times. $\bf2^\textbf{ nd}$ quanta of time: $1 + 2 + 4 + 8 + 15 = 30$ `JEET answered Oct 25, 2019 • edited Oct 28, 2021 by `JEET `JEET comment Share Follow See all 2 Comments See all 2 2 Comments reply yadavg123 commented Apr 15, 2020 reply Follow Share `JEET Sir, How did u get these 1, 2, 4, 8, 15? 0 votes 0 votes `JEET commented Oct 28, 2021 reply Follow Share Standard working of $\mathbf{CTSS}$. For more details please refer:: https://cs.stackexchange.com/questions/52271/can-you-explain-this-exercise-solution-to-me 0 votes 0 votes Please log in or register to add a comment.