The Gateway to Computer Science Excellence
0 votes
6 views
Consider a $4-TB$ disk that uses $4-KB$ blocks and the free-list method. How many block addresses can be stored in one block?
in Operating System by Veteran (59.3k points) | 6 views

1 Answer

0 votes

Answer:

The size of disk$=4\;\text{TB}=4\times 2^{40}$

Size of a block$=4\;\text{KB} = 4 \times 2^{10}$

So, the number of blocks on the disk $=\frac{\text{Size of disk}}{\text{Size of block}} \\= \frac{2^{40}}{2^{10}} \\= 2^{30}$

So, Total number of blocks$=2^{30} \;\text{Blocks}$

by Boss (19.2k points)
edited by

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,737 questions
57,385 answers
198,557 comments
105,368 users