Register

Andrew S. Tanenbaum (OS) Edition 4 Exercise 5 Question 19 (Page No. 431)

352 views

1 Answer

0 votes
0 votes

Answer:

Total number of rotations in $1$ second$=120$ (From previous problem Data)

In $1$ rotation number of bytes that pass under the head$=500\times 512$

$\therefore$Number of bytes that disk can read $=256000\;\text{Bytes per rotation} \\=30,720,000 \;\text{bytes per sec}$

User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

0 votes
0 votes
1 answer
2
admin asked Oct 28, 2019
747 views
Andrew S. Tanenbaum (OS) Edition 4 Exercise 5 Question 27 (Page No. 431)
If a disk has double interleaving, does it also need cylinder skew in order to avoid missing data when making a track-to-track seek? Discuss your answer.
If a disk has double interleaving, does it also need cylinder skew in order to avoid missing data when making a track-to-track seek? Discuss your answer.
User Avatar
0 votes
0 votes
0 answers
3
admin asked Oct 28, 2019
349 views
Andrew S. Tanenbaum (OS) Edition 4 Exercise 5 Question 25 (Page No. 431)
What are the advantages and disadvantages of optical disks versus magnetic disks?
What are the advantages and disadvantages of optical disks versus magnetic disks?
User Avatar
0 votes
0 votes
0 answers
4
admin asked Oct 28, 2019
213 views
Andrew S. Tanenbaum (OS) Edition 4 Exercise 5 Question 24 (Page No. 431)
Why are optical storage devices inherently capable of higher data density than magnetic storage devices? Note: This problem requires some knowledge of high-school physics and how magnetic fields are generated.
Why are optical storage devices inherently capable of higher data density than magnetic storage devices? Note: This problem requires some knowledge of high-school physics...
User Avatar
Link Copied!