2 votes 2 votes If $A=\{x,y,z\}$ and $B=\{u,v,w,x\}, $ and the universe is $\{s,t,u,v,w,x,y,z\}$. Then $(A \cup \overline{B}) \cap (A \cap B)$ is equal to $\{u,v,w,x\}$ $\{ \: \}$ $\{u,v,w,x,y,z\}$ $\{u,v,w\}$ Set Theory & Algebra isro-2020 discrete-mathematics set-theory&algebra set-theory easy + – Satbir asked Jan 13, 2020 edited Jan 24 by makhdoom ghaya Satbir 1.3k views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply vijay kumar 2 commented Jan 13, 2020 reply Follow Share i have not marked any option so marks will be given to all or only who have attempted? 0 votes 0 votes Tuhin Dutta commented Jan 13, 2020 reply Follow Share The question would be canceled. 0 votes 0 votes Please log in or register to add a comment.
5 votes 5 votes $\bar{B}=\{s,t,u,v,w,x,y,z\}-\{u,v,w,x\} = \{s,t,y,z\}$ $(A\cup\bar{B})=\{s,t,x,y,z\}$ $(A\cap B)=\{x\}$ $(A\cup \bar{B})\cap(A\cap B)=\{s,t,x,y,z\}\cap\{x\}=\{x\}$ But there was no such option. habedo007 answered Jan 13, 2020 habedo007 comment Share Follow See all 2 Comments See all 2 2 Comments reply Maguluri Bhaskar commented May 14, 2020 reply Follow Share A={x,y,z} B={u,v,w,z} U={s,t,u,v,w,x,y,z} B¯ = U-B = {s,t,u,v,w,x,y,z}-{u,v,w,z} => {s,t,x,y} A U B¯ = { s,t,x,y,z} A ∩ B = { x,y,z} ∩ {u,v,w,z } => { z } (A U B¯) ∩ (A ∩ B) = { s,t,x,y,z} ∩ { z } => {z} Ans is {z} not {x} 0 votes 0 votes Hira Thakur commented Jul 5, 2023 reply Follow Share set $B$ having element $(u,v,w,x)$ but you taken as $(u,v,w,z)$ 0 votes 0 votes Please log in or register to add a comment.