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If every non-key attribute functionally dependent on the primary key, then the relation will be in

  1. First normal form
  2. Second normal form
  3. Third normal form
  4. Fourth Normal form
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12 Answers

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It is assumed that no partial dependency and transitive dependency exist in the given question, so it in 3NF.
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Since all the non-prime attributes are FULLY dependent functionally on the Primary Key, so it in 2NF.

Hence the option B is correct.
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Answer :- C

Let's say A->B  . in the definition of 3NF , A is superkey/superset of B . or

 

no non-prime attribute is functionally dependent on other non-prime attribute .

 

in the question they said : every non-key attribute functionally dependent on the primary key

 

it means , from the second definition we can say that if A is prime attribute  and B is non-prime attribute , then this satisfy 3NF property 

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In my view it is in 3NF because for 1NF only atomic value, 2NF there should be no partial dependency meaning no non-prime key should be dependent of proper subset of candidate key and in 3NF there should not be any transistive dependencies of non prime attributes.
Answer:

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